Formula

$$ x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} $$

$$ f_2=50\times \log{\Bigg [ \frac{100}{\sqrt{1+\frac{\sum\limits_{t=1}^n(R_t-T_t)^2}{n}}}}\Bigg ] $$ 
\\[
 x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} 
\\]
$$
f_2=50\times \log{\Bigg [ \frac{100}{\sqrt{1+\frac{\sum\limits_{t=1}^n(R_t-T_t)^2}{n}}}}\Bigg ]
$$
$$ \ce{H2O} $$
$$ \ce{A ->[H2O] B} $$
$$\pu{1.2E3 kJ}$$

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